Diket pola bilangan geometri 3,6,42,24,48 tentukan U9 U12
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Jawab:
r = U2 ÷ U1
r = 6 ÷ 3 = 2
U9 = a.r^n-1
U9 = 3 × 2^9-1
U9 = 3 × 2^8
U9 = 3 × 256
= 768
U12 = a.r^n-1
U12 = 3 × 2^12-1
U12 = 3 × 2^11
U12 = 3 × 2048
= 6.144
MAAF KALO SALAH
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